If it's not what You are looking for type in the equation solver your own equation and let us solve it.
-4.9x^2+5x+1=0
a = -4.9; b = 5; c = +1;
Δ = b2-4ac
Δ = 52-4·(-4.9)·1
Δ = 44.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{44.6}}{2*-4.9}=\frac{-5-\sqrt{44.6}}{-9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{44.6}}{2*-4.9}=\frac{-5+\sqrt{44.6}}{-9.8} $
| -1.8=0.2+c/0.2 | | 115=4x-3 | | 1/x=7x-9/2x+4 | | a/0.8-2.4=-0.15 | | 2.5-2.5y=5 | | 5x+20x-1=5(5x+9) | | 3(3x+12)-15x=2(3-3x) | | G(4)=-3x2-2 | | 14x-18=6+6x | | 7x+17x-3=6(4x+7) | | 0.3+6=0.3(n+6 | | 10x+8=10x-3 | | 2x-13=x-13 | | 8(16.5-1.16y)+9y=129 | | -5(2+5r)=-210 | | 117=179-u | | 199=36-x | | Z=Y/3x6 | | 199=36-c | | (1÷3)πr²(8.5)=142 | | w12+7=7 | | a+3a=180° | | Y-10=1/4(x-10) | | -16t^3+100t=50 | | (3x+2)^2/2=8 | | |13x-1|=0 | | G-2=g-5 | | (2x-12)+(9x-7)+(2x+17)=180 | | (6x+2)=(x+19)+(2x+1) | | (3x-10)+(6x+5)+(4x-10)=180 | | -5(v-2)+7=37 | | -100=-4.9×t^2 |